Archimede's Principle
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Archimede's principle states that a body immersed in a fluid is buoyed up with a force equal to the weight of the displaced fluid. |
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A 10-mL body, "weighting" 50 grams, will displace 10 mL of H2O. This amount of water has a mass of 10 grams because the density of H2O is 1-g/mL. Therefore, the 50-g body will weigh 10-grams less, or 40 grams when immersed in the liquid. |
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Mass of body |
50-g |
50-g |
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Volume of body |
10-mL |
. |
|
Volume of fluid displaced |
10-mL |
. |
|
Mass of fluid displaced (H2O has a density of 1-g/mL) |
10-g |
- 10-g |
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Mass of body while in water (subtract) |
. |
40-g |
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A 5 mL body with a mass in air of 40-g is immersed in CCl4 (carbon tetrachloride) whose density is 1.59 g/mL. What is the apparent mass of the body while submerged in the CCl4? |
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Solution: |
A submerged 5-mL body will displace 5-mL of liquid. Since the density of CCl4 is 1.59-g/mL, the 5-mL of CCl4 will weigh 7.95-g. Therefore the mass of the submerged body will weigh 40-g minus 7.95-g or 32.05-g. |
|
Mass of body |
40-g |
40-g |
|
Volume of body |
5-mL |
. |
|
Volume of fluid displaced |
5-mL |
. |
|
Mass of fluid displaced |
7.95-g |
- 7.95-g |
|
Mass of body while in water (subtract) |
. |
32.05-g |
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You are deep-sea fishing off of Catalina Island. You catch a yellowfin tuna and accurately estimate that the tuna has a volume of 20-L (20,000-mL), and a mass in sea water of 30-kg. If the density of sea water is 1.1 g/mL, what will be the mass of the tuna when lifted from the water. |
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Mass of body in water |
30,000-g |
30,000-g |
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Volume of body |
20,000-mL |
. |
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Volume of fluid displaced |
20,000-mL |
. |
|
Mass of fluid displaced |
22,000-g |
+22,000-g |
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Mass of body while in air (add) |
. |
52,000-g |