A. Total Number of flowers = 1190 + 1070 + 240 = 2500
240 thin coat/2500 total = 0.096
q2 = 0.096, therefore the recessive
allelic frequency is q = 0.31
B. p + q = 1
p = 1 - 0.31
p = 0.69 - dominant allelic frequency
C.
| Genotype | Designation | Frequency | Percent |
| Homozygous Dominant | pp or p2 | (0.69)2 = 0.48 | 48% |
| Heterozygote | pq | 2(0.69)(0.31) = 0.43 | 43% |
| Homozygous Recessive | (0.031)2 = 0.096 | 9.6% |